The shape attribute for numpy arrays returns the dimensions of the array. If Y has n rows and m columns, then Y.shape is (n,m). So Y.shape[0] is n.
python - What does .shape [] do in "for i in range (Y.shape [0 ...
Shape n, expresses the shape of a 1D array with n items, and n, 1 the shape of a n-row x 1-column array. (R,) and (R,1) just add (useless) parentheses but still express respectively 1D and 2D array shapes, Parentheses around a tuple force the evaluation order and prevent it to be read as a list of values (e.g. in function calls).
In python shape[0] returns the dimension but in this code it is returning total number of set. Please can someone tell me work of shape[0] and shape[1]? Code: m_train = train_set_x_orig.shape[0]
On the other hand, x.shape is a 2-tuple which represents the shape of x, which in this case is (10, 1024). x.shape[0] gives the first element in that tuple, which is 10. Here's a demo with some smaller numbers, which should hopefully be easier to understand.
python - x.shape [0] vs x [0].shape in NumPy - Stack Overflow
While searching on this problem, I have noticed that there is a way to identify which shape has been selected whereas I still doesn't know How to get the name of the shape I have clicked or is there a way to refer to that clicked shape in VBA? Thank you!
How to identify the clicked shape name in VBA - Stack Overflow