is there a possibility that casting a double created via Math.round() will still result in a truncated down number No, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places. But after rounding, there will not be any fractional parts remaining. Here are the docs from Math.round(double): Returns the closest long to ...
Casting this to a string (by whichever method) before testing it results in a failure: either an exception that's unhandled, or the string "UNDEFINED" which is indistinguishable from the user input "UNDEFINED". Of course, it would be better and much more expected if JS converts it to an empty string, but it's browser-specific.
Casting can be used to clearly state that you are calling a child method and not a parent method. So in this case it's always a downcast or more correctly, a narrowing conversion.
Casting between function pointers and regular pointers (e.g. casting a void ()(void) to a void). Function pointers aren't necessarily the same size as regular pointers, since on some architectures they might contain extra contextual information. This will probably work ok on x86, but remember that it's undefined behavior.
c - Casting a function pointer to another type - Stack Overflow
You can cast a subtype to its base type. But you are casting an instance of the base type to the subtype. An EmployeeProfile is-an Employee. Not necessarily the other way around. So this would work:
C++ int float casting Asked 14 years, 11 months ago Modified 4 years, 2 months ago Viewed 335k times