Nature: Trigonal Planar Bis(carbene)Cu(I) Complexes Enable Divergent H2 Activation with H2O for Accelerated Olefin Hydrogenation
Trigonal Planar Bis(carbene)Cu(I) Complexes Enable Divergent H2 Activation with H2O for Accelerated Olefin Hydrogenation
Nature: Spectroscopic and Theoretical Investigation of High-Spin Square-Planar and Trigonal Fe(II) Complexes Supported by Fluorinated Alkoxides
Spectroscopic and Theoretical Investigation of High-Spin Square-Planar and Trigonal Fe(II) Complexes Supported by Fluorinated Alkoxides
Even though the molecule will have a structure that allows for it to exist in a planar conformation, there may be some/many that do not persist in a planar conformation due to steric effects, or complex three dimensional geometries.
The molecule $\ce { [PdCl4]^2-}$ is diamagnetic, which indicates a square planar geometry as all eight d electrons are paired in the lower-energy orbitals. However, $\ce { [NiCl4]^2-}$ is also $\mathr...
Why is $\ce { (NH4)2 [CuCl4]}$ square planar complex but $\ce {Cs2 [CuCl4]}$ is tetrahedral even though both have same oxidation number of copper and same ligands?
inorganic chemistry - Why is (NH4)2 [CuCl4] square planar complex but ...
Why do square planar coordination compounds of type $\ce{[Mabcd]}$ not show optical activity, although they contain 4 different ligands (i.e. chiral central metal atom)?
It is not square planar but a Jahn-Teller distorted octahedron. You can check out its structure in the image below. You can fill electrons into the energy diagram in a standard fashion. You will arrive at the $\mathrm {d}_ {x^2-y^2}$ orbital for the unpaired electron — the one pointing towards the four ammine ligands.
Why is tetraamminecopper (II) a square planar and not a tetrahedral ...