The shape attribute for numpy arrays returns the dimensions of the array. If Y has n rows and m columns, then Y.shape is (n,m). So Y.shape[0] is n.
While searching on this problem, I have noticed that there is a way to identify which shape has been selected whereas I still doesn't know How to get the name of the shape I have clicked or is there a way to refer to that clicked shape in VBA? Thank you!
MSN: Why Do Snowflakes Always Have Six Sides But Never Look The Same?
We’ve all heard it—no two snowflakes are alike. However, they all seem to share that same six-sided shape, so what’s going on? Why do they follow the same rulebook for structure but still end up ...
Why Do Snowflakes Always Have Six Sides But Never Look The Same?
python - What does .shape [] do in "for i in range (Y.shape [0 ...
Shape n, expresses the shape of a 1D array with n items, and n, 1 the shape of a n-row x 1-column array. (R,) and (R,1) just add (useless) parentheses but still express respectively 1D and 2D array shapes, Parentheses around a tuple force the evaluation order and prevent it to be read as a list of values (e.g. in function calls).
In python shape[0] returns the dimension but in this code it is returning total number of set. Please can someone tell me work of shape[0] and shape[1]? Code: m_train = train_set_x_orig.shape[0]
On the other hand, x.shape is a 2-tuple which represents the shape of x, which in this case is (10, 1024). x.shape[0] gives the first element in that tuple, which is 10. Here's a demo with some smaller numbers, which should hopefully be easier to understand.